## ==================================================================== ## Mammary Model Neal and Thornley, 1983 ## includes changes made by Baldwin, 1995 ## includes substrate (caa cgl) ## includes milk lactose (Lm) ## milk yield est from Lm ## ## ## ==================================================================== #load packages library(deSolve) library(FME) library(ggplot2) library(gridExtra) # SECTION 1. Initial conditions and parameters times = seq(0, 305, by = 0.1) #Specify parameters parms = c(Kh = 0.0102, #hormone decay rate for LHor /d (KLhor) Cu = 1000, #number of udder cells (ucells) Vm = 1, #max enzyme synthetic capacity /cell/d (Vusyn) KH = 0.2, #enzymatic response to hormone kg hormone/m3 (Kusyn) Ks = 0.1, #enzyme degradation rate constant /d (Kudeg) KR = 3, #milk secretion rate mm constant:persistency kg milk (KmlkI) Ksm = 0.2, #enzyme degrade rate constant indiced by milk retention /d (KudegM) Mh = 27, #half response pt for degrade due to Umilk kg (KmDeg) Kr = 0.048, #milk averaging constant /d (TaveM) Km = 0.00506, #milk secretion constant kg/uenz/d (VFaTmV, VAcTmV, VAaPmV, VGmLmV) KM = 4.43, #milk removal constant kg=4.43 (Kmilk=2.91/umlkcr) Mm = 30, #milk capacity of animal kg (Mlkmax) theta = 10, #parameter of equation (theta) Rc = 40, #milk removal by suckling calf kg/d (umlkcr=1) PCLm = 0.048, #percent lactose in milk VGlLmV = 0.0039, #maximal velocity glucose to lactose synthesis in mammary KGlLmV = 0.003, #Km glucose to lactose synthesis in mammary cGl = 0.0036, #blood concentration of glucose = 63 mg/dl KAaLmV = 0.002, #Km amino acids to lactose sytnesis in mammary cAa = 0.004, #blood concentration of total amino acids 0.0025-0.005 Kmilk = 2.91) #udder milk retention feedback effect #Specify initial values for state Variables qinit = c(H = 1, #hormone effector of udder enzymes kg/m3 (Lhor) #M = 0, #quantity of milk in cow kg (Umilk) ULm = 0.1, #udder milk lactose kg TMlkLm = 0, #total milk lactose kg Cs = 520, #number of udder enzymes (uenz) Mave = 0) #time avg or Umilk kg (Umave) #tvmlk = 0, #total milk yield kg # SECTION 2. Derivatives eqns = function(t, q, parms) { with(as.list(c(parms, q)), { #Eq1:lactation hormones decrease as lactation progresses in kg/m3 dH = -Kh * H #Eq5:udder enzyme growth influenced by lactation hormone Ps = Vm * Cu * H / (KH + H) #Eq6:udder enzyme death influenced by milk retention Ls = Cs * (Ks + Ksm * ((Mave / Mh)^theta / (1.0 + (Mave / Mh)^theta))) #Eq7:number of udder enzymes dCs = Ps - Ls #EFFECTS OF SUBSTRATE AVAILABILITY - Lactose M = ULm / PCLm Kminh = (Mm - M)/(Mm - M + Kr) #milk retention effects GlLmV = VGlLmV * Cs * Kminh / (1 + KGlLmV / cGl + KAaLmV / cAa) dMlkLm = ULm * Kmilk dULm = GlLmV * 0.5 * 0.342 - dMlkLm dmilk = dMlkLm / PCLm TMlkLm = dMlkLm tvmlk = TMlkLm / PCLm #eq8:rate of secretion of milk kg/d is proportional to number of udder enzymes Cs Pm = Km * Cs * Kminh #eq9:rate of removal of milk in kg/d #dmilk = (M/(KM + M))*Rc #Eq14:rate of change in secretion of milk in kg/d is proportional to uenz and inhibited by retained milk #as approaches max capacity assuming no milk pulsing function m(t) in paper #dM = Pm - dmilk #Eq16:length of time M is high influences rate of secretion of milk in kg over 1/kr d dMave = Kr * (M - Mave) #tvmlk = dmilk res = c(dH, dULm, dMlkLm, dCs, dMave) list(res) }) } # SECTION 3. Results integrate numerically out1 = rk(qinit, times, eqns, parms, method = "rk4") df = as.data.frame(out1) #Add non-integrated variables to dataframe df$M = df$ULm/(parms["PCLm"]) df$dmilk = df$ULm*parms["Kmilk"]/(parms["PCLm"]) df$dMlkLm = df$ULm*parms["Kmilk"] df$tvmlk = df$TMlkLm/(parms["PCLm"]) #see what you have in the first rows head(df, 70) #see what you have in the last rows tail(df, 70) #1 Create plots colnames(df) matplot(x=df$time, y=df[,6:8], type = "l", lwd = 3, col = c(6,7,8), ylim=c(0,60), xlab="Time,d", ylab="Amount,kg") legend("topright", c("Mave", "M", "dmilk"), fill=c(6,7,8), cex = .8) matplot(x=df$time, y=df[,5], type = "l", lwd = 3, col = c(5), ylim=c(0,8000), xlab="Time,d", ylab="Amount") legend("topright", c("Cs"), fill=c(5), cex = .8) matplot(x=df$time, y=df[,2:3], type = "l", lwd = 3, col = c(2,3), ylim=c(0,1), xlab="Time,d", ylab="Amount,kg") legend("topright", c("H", "ULm"), fill=c(2,3), cex = .8)